Optimal. Leaf size=138 \[ \frac {15 d (b c-a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b^3}+\frac {5 d \sqrt {a+b x} (c+d x)^{3/2}}{2 b^2}-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}}+\frac {15 \sqrt {d} (b c-a d)^2 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{4 b^{7/2}} \]
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Rubi [A]
time = 0.05, antiderivative size = 138, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 5, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.263, Rules used = {49, 52, 65, 223,
212} \begin {gather*} \frac {15 \sqrt {d} (b c-a d)^2 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{4 b^{7/2}}+\frac {15 d \sqrt {a+b x} \sqrt {c+d x} (b c-a d)}{4 b^3}+\frac {5 d \sqrt {a+b x} (c+d x)^{3/2}}{2 b^2}-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}} \end {gather*}
Antiderivative was successfully verified.
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Rule 49
Rule 52
Rule 65
Rule 212
Rule 223
Rubi steps
\begin {align*} \int \frac {(c+d x)^{5/2}}{(a+b x)^{3/2}} \, dx &=-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}}+\frac {(5 d) \int \frac {(c+d x)^{3/2}}{\sqrt {a+b x}} \, dx}{b}\\ &=\frac {5 d \sqrt {a+b x} (c+d x)^{3/2}}{2 b^2}-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}}+\frac {(15 d (b c-a d)) \int \frac {\sqrt {c+d x}}{\sqrt {a+b x}} \, dx}{4 b^2}\\ &=\frac {15 d (b c-a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b^3}+\frac {5 d \sqrt {a+b x} (c+d x)^{3/2}}{2 b^2}-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}}+\frac {\left (15 d (b c-a d)^2\right ) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx}{8 b^3}\\ &=\frac {15 d (b c-a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b^3}+\frac {5 d \sqrt {a+b x} (c+d x)^{3/2}}{2 b^2}-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}}+\frac {\left (15 d (b c-a d)^2\right ) \text {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{4 b^4}\\ &=\frac {15 d (b c-a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b^3}+\frac {5 d \sqrt {a+b x} (c+d x)^{3/2}}{2 b^2}-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}}+\frac {\left (15 d (b c-a d)^2\right ) \text {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{4 b^4}\\ &=\frac {15 d (b c-a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b^3}+\frac {5 d \sqrt {a+b x} (c+d x)^{3/2}}{2 b^2}-\frac {2 (c+d x)^{5/2}}{b \sqrt {a+b x}}+\frac {15 \sqrt {d} (b c-a d)^2 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{4 b^{7/2}}\\ \end {align*}
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Mathematica [A]
time = 0.25, size = 124, normalized size = 0.90 \begin {gather*} \frac {\sqrt {c+d x} \left (-15 a^2 d^2-5 a b d (-5 c+d x)+b^2 \left (-8 c^2+9 c d x+2 d^2 x^2\right )\right )}{4 b^3 \sqrt {a+b x}}+\frac {15 \sqrt {d} (b c-a d)^2 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {d} \sqrt {a+b x}}\right )}{4 b^{7/2}} \end {gather*}
Antiderivative was successfully verified.
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Mathics [F(-1)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.06, size = 0, normalized size = 0.00 \[\int \frac {\left (d x +c \right )^{\frac {5}{2}}}{\left (b x +a \right )^{\frac {3}{2}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.38, size = 439, normalized size = 3.18 \begin {gather*} \left [\frac {15 \, {\left (a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2} + {\left (b^{3} c^{2} - 2 \, a b^{2} c d + a^{2} b d^{2}\right )} x\right )} \sqrt {\frac {d}{b}} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \, {\left (2 \, b^{2} d x + b^{2} c + a b d\right )} \sqrt {b x + a} \sqrt {d x + c} \sqrt {\frac {d}{b}} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) + 4 \, {\left (2 \, b^{2} d^{2} x^{2} - 8 \, b^{2} c^{2} + 25 \, a b c d - 15 \, a^{2} d^{2} + {\left (9 \, b^{2} c d - 5 \, a b d^{2}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{16 \, {\left (b^{4} x + a b^{3}\right )}}, -\frac {15 \, {\left (a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2} + {\left (b^{3} c^{2} - 2 \, a b^{2} c d + a^{2} b d^{2}\right )} x\right )} \sqrt {-\frac {d}{b}} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {b x + a} \sqrt {d x + c} \sqrt {-\frac {d}{b}}}{2 \, {\left (b d^{2} x^{2} + a c d + {\left (b c d + a d^{2}\right )} x\right )}}\right ) - 2 \, {\left (2 \, b^{2} d^{2} x^{2} - 8 \, b^{2} c^{2} + 25 \, a b c d - 15 \, a^{2} d^{2} + {\left (9 \, b^{2} c d - 5 \, a b d^{2}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{8 \, {\left (b^{4} x + a b^{3}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (c + d x\right )^{\frac {5}{2}}}{\left (a + b x\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.04, size = 282, normalized size = 2.04 \begin {gather*} \frac {2 \left (\left (\frac {\frac {1}{8}\cdot 2 b^{4} d^{2} \sqrt {c+d x} \sqrt {c+d x}}{b^{5} \left |d\right |}+\frac {\frac {1}{8} \left (5 b^{4} d^{2} c-5 b^{3} d^{3} a\right )}{b^{5} \left |d\right |}\right ) \sqrt {c+d x} \sqrt {c+d x}+\frac {\frac {1}{8} \left (-15 b^{4} d^{2} c^{2}+30 b^{3} d^{3} a c-15 b^{2} d^{4} a^{2}\right )}{b^{5} \left |d\right |}\right ) \sqrt {c+d x} \sqrt {a d^{2}-b c d+b d \left (c+d x\right )}}{a d^{2}-b c d+b d \left (c+d x\right )}+\frac {2 \left (-15 a^{2} d^{4}+30 a b c d^{3}-15 b^{2} c^{2} d^{2}\right ) \ln \left |\sqrt {a d^{2}-b c d+b d \left (c+d x\right )}-\sqrt {b d} \sqrt {c+d x}\right |}{8 b^{3} \sqrt {b d} \left |d\right |} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (c+d\,x\right )}^{5/2}}{{\left (a+b\,x\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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